x/x^2-4x-32-5/x+4

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Solution for x/x^2-4x-32-5/x+4 equation:


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

x/(x^2)-(4*x)-(5/x)-32+4 = 0

x/(x^2)-4*x-5*x^-1-32+4 = 0

-4*x^1-4*x^-1-28*x^0 = 0

(-4*x^2-28*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(-4*x^2-28*x^1-4*x^0) = 0

x^1

-4*x^2-28*x-4 = 0

-4*x^2-28*x-4 = 0

DELTA = (-28)^2-(-4*(-4)*4)

DELTA = 720

DELTA > 0

x = (720^(1/2)+28)/(-4*2) or x = (28-720^(1/2))/(-4*2)

x = (12*5^(1/2)+28)/(-8) or x = (28-12*5^(1/2))/(-8)

x in { (12*5^(1/2)+28)/(-8), (28-12*5^(1/2))/(-8)}

x in { (12*5^(1/2)+28)/(-8), (28-12*5^(1/2))/(-8) }

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